In working with problems involving fractions that have more than one mathematical operation; i.e (Of, +, ×, ÷, – ). We use what we called BODMAS Rule in Mathematics to work it. BODMAS is an acronym that stands for (B-Bracket, O-Of, D-Division, M-Multiplication, A-Addition, and S-Subtraction).

There are steps to follow when working on a mathematical problem with more than one sign.

## BODMAS Rule in Mathematics

The following rules in **BODMAS** should be followed accordingly when dealing with mathematical problems with more than one sign (**of,+,-,÷,×** ).

Step 1: Deal with anything involving **brackets** first (if there are any in a mathematical problem). i.e **( )**

Step 2: Work with O = **Of** (if there is any). Note ‘**Of’=** **Multiplication** **(×)**

Step 3: Deal with **Division** ( if there is any) i.e **‘÷’**

Step 4: Deal with **Multiplication** (if there is any) i.e** ‘×’**

Step 5: Deal with the **Addition** (if there is any ) i.e** ‘+’**

Step 6: Deal with **Subtraction** (if there is any ) i.e **‘-‘**

Let’s look at the examples below using BODMAS

\text{Evaluate } (1\frac{1}{3} ×2\frac{1}{6})+(1\frac{1}{2}÷\frac{5}{6})\\ Answer: \text{Since there is bracket, deal}\\\text{with bracket first} \space(1\frac{1}{3}×2\frac{1}{6})+(1\frac{1}{2}÷\frac{5}{6})\\=(\frac{(1×3)+1}{3}×\frac{(2×6)+1}{6})\\+(\frac{(1×2)+1}{2}÷\frac{5}{6})= (\frac{4}{3}×\frac{13}{6})\\+(\frac{3}{2}÷\frac{5}{6})\\=(\frac{26}{6})+(\frac{3}{2}×\frac{6}{5})=\frac{26}{6}+\frac{18}{10}\\=\frac{13}{3}+\frac{9}{5}\\ \text{ the LCM of 3 and 5 is 15}\space =\frac{13}{3}+\frac{9}{5}\\=\frac{(5×13)+(3×9)}{15}=\frac{65+27}{15}=\frac{92}{15}\\=6\frac{2}{15}

This is pretty good, right? All Mathematical problems with more than one sign is done the same way.

On how to divide fractions click here